x^2-2*x+(2^2+3^2)=0

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Solution for x^2-2*x+(2^2+3^2)=0 equation: 



x^2-2x+(2^2+3^2)=0

We add all the numbers together, and all the variables

x^2-2x+13=0

a = 1; b = -2; c = +13;
Δ = b2-4ac
Δ = -22-4·1·13
Δ = -48
Delta is less than zero, so there is no solution for the equation

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